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JEE Main2018ChemistryThermodynamics (C)Actual

The combustion of benzene l gives CO 2 g and H 2 O l . Given that heat of combustion of benzene at constant volume is - 3263 .9 kJ mol - 1 at 25 ° C ; the heat of combustion in kJ mol - 1 of benzene at constant pressure will be R = 8 .314 JK - 1 mol - 1

Options

  1. A- 3267.6
  2. B4152.6
  3. C- 452.46
  4. D3260

Correct answer

A. - 3267.6

Step-by-step solution

C 6 H 6 l + 15 2 O 2 g → 6 CO 2 g + 3 H 2 O ( I )     ∴   ∆ n g =   - 3 2 Use, ΔH = ΔU + Δn g RT = - 3263.5 × 10 3 - 3 2 × 8.314 × 298 × 10 - 3   = - 3267 .6   kJ   mol - 1

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