If 100 mole of H 2 O 2 decompose at 1 bar and 300 K , the work is done ( kJ ) by one mole of O 2 ( g ) as it expands against 1 bar pressure is: 2 H 2 O 2 l ⇌ 2 H 2 O l + O 2 ( g ) R = 8 .3 J K - 1 mol - 1

Step-by-step solution

Irreversible process W = P ∆ V = nRT 2 H 2 O 2 100   mol l ⇌ 2 H 2 O l + O 2      50   mol g ∴ 100   mol   H 2 O 2 on decomposition will give 50   mol   O 2 = 50 × 8.3 × 300 = 124500   J =124.50   kJ