JEE Main2016ChemistryThermodynamics (C)Actual
A reaction at 1 bar is non-spontaneous at low temperature but becomes spontaneous at high temperature. Identify the correct statement about the reaction among the following:
Options
- A∆ H is negative while ∆ S is positive
- BBoth ∆ H and ∆ S are negative
- C∆ H is positive while ∆ S is negative
- DBoth ∆ H and ∆ S are positive
Correct answer
D. Both ∆ H and ∆ S are positive
Step-by-step solution
∆ G   =   ∆ H   –   T ∆ S (For Spontaneity) ( ∆ G   <   0 ) So If ∆ H   >   0     and     ∆ S   >   0   for spontaneity then the process is feasible at high temperature and non-feasible at low temperature.