The increase of pressure on i c e ⇌ w a t e r system at constant temperature will lead to:

Step-by-step solution

H 2 O s ⇌ H 2 O ( l ) At melting point of H 2 O at (273 K = T) dG = VdP - SdT At constant temperature d ∆ G = ∆ V d P = M ρ L - M ρ S d P ρ L = D e n s i t y   o f   L i q .   H 2 O ρ S = D e n s i t y   o f   i c e d ∆ G = M ρ S   -   ρ L ρ L   ⋅   ρ S d P Integrating ∆ G = M ρ S   -   ρ L ρ L   ⋅   ρ S ( P - 1 ) Pressure increased from 1 atm to P at