For complete combustion of ethanol, C 2 H 5 OH l + 3 O 2 g → 2 CO 2 g + 3 H 2 O l , the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol -1 at 2 5 ℃ . Assuming ideality the Enthalpy of combustion, &#916

Question

For complete combustion of ethanol, C 2 H 5 OH l + 3 O 2 g &#8594; 2 CO 2 g + 3 H 2 O l , the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol -1 at 2 5 &#8451; . Assuming ideality the Enthalpy of combustion, &#916; c H , for the reaction will be: R = 8.314 kJ mol -1

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Correct answer: A. - 1366.95 kJ mol -1

Δ n g = Gaseous moles products - Gaseous moles reactants = 2 - 3 = -1 mole Δ H = Δ E + Δ n g RT = - 1364.47 - 1 × 8.314 × 1 0 - 3 × 2 9 8 [The value of R must be converted into kJ, so it is multiplied by 10 -3 ] = - 1364.47 - 2.49 = - 1366.96 kJ m -1

For complete combustion of ethanol, C 2 H 5 OH l + 3 O 2 g → 2 CO 2 g + 3 H 2 O l , the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol -1 at 2 5 ℃ . Assuming ideality the Enthalpy of combustion, Δ c H , for the reaction will be: R = 8.314 kJ mol -1

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More from Thermodynamics (C)

For complete combustion of ethanol, C 2 H 5 OH l + 3 O 2 g &#8594; 2 CO 2 g + 3 H 2 O l , the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol -1 at 2 5 &#8451; . Assuming ideality the Enthalpy of combustion, &#916; c H , for the reaction will be: R = 8.314 kJ mol -1

Options

Correct answer

Step-by-step solution

More from Thermodynamics (C)

For complete combustion of ethanol, C 2 H 5 OH l + 3 O 2 g → 2 CO 2 g + 3 H 2 O l , the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol -1 at 2 5 ℃ . Assuming ideality the Enthalpy of combustion, Δ c H , for the reaction will be: R = 8.314 kJ mol -1