JEE Main2012ChemistryThermodynamics (C)Actual
The entropy of a sample of a certain substance increases by 0.836 ~J ~K ⁻¹ on adding reversibly 0.3344 ~J of heat at constant temperature. The temperature of the sample is:
Options
- A2.5 ~K
- B0.3 ~K
- C0.016 ~K
- D0.4 ~K
Correct answer
D. 0.4 ~K
Step-by-step solution
S= H T ; T= H S = 0.3344 0.836 =0.4 ~K