JEE Main2009ChemistryThermodynamics (C)Actual
On the basis of the following thermochemical data: ( fG ^ H _ (aq) ⁺=0 ) aligned & H ₂ O ( ) H ⁺( aq )+ OH ⁻( aq ) ; H =57.32 ~kJ & H ₂( ~g )+ 1 2 O ₂( ~g ) H ₂ O ( ) ; H =-286.20 ~kJ aligned The value of enthalpy of formation of OH ⁻ ion at 25^ C is:
Options
- A-22.88 ~kJ
- B-228.88 ~kJ
- C+228.88 ~kJ
- D-343.52 ~kJ
Correct answer
B. -228.88 ~kJ
Step-by-step solution
By adding the two given equations, we have H _ 2( ~g ) + 1 2 O _ 2( ~g ) H _ ( aq ) ⁺+ OH _ ( aq ) ⁻ ; H =-228.88 Kj Here H _ f ^ of H _ ( aq ) ⁺=0 H _ f ^ of OH ⁻=-228.88 ~kJ