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JEE Main2008ChemistryThermodynamics (C)Actual

Standard entropy of X₂, Y₂ and X Y₃ are 60,40 and 50 JK ⁻¹ ~mol ⁻¹ , respectively. For the reaction, 1 2 X₂+ 3 2 Y₂ X Y₃, H =-30 ~kJ , to be at equilibrium, the temperature will be

Options

  1. A1250 ~K
  2. B500 ~K
  3. C750 ~K
  4. D1000 ~K

Correct answer

C. 750 ~K

Step-by-step solution

aligned & 1 2 X₂+ 3 2 Y₂ X Y₃ & S_ reaction =50- ( 3 2 40+ 1 2 60 )=-40 Jmol ⁻¹ & G= H-T S & at equilibrium G=0 aligned aligned & H = T S & 30 10^3= T 40 & T =750 ~K aligned

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