JEE Main2006ChemistryThermodynamics (C)Actual
The enthalpy changes for the following processes are listed below: array ll Cl ₂( ~g )=2 Cl ( g ), & 242.3 ~kJ ~mol ⁻¹ I ₂( ~g )=2 I ( g ), & 151.0 ~kJ ~mol ⁻¹ ICl ( g )= I ( g )+ Cl ( g ), & 211.3 ~kJ ~mol ⁻¹ I ₂( ~s )= I ₂( ~g ), & 62.76 ~kJ ~mol ⁻¹ array Given that the standard states for iodine and chlorine are I ₂( ~s ) and Cl ₂( ~g ) , the standard enthalpy of formation for ICl ( g ) is
Options
- A-14.6 ~kJ ~mol ⁻¹
- B-16.8 ~kJ ~mol ⁻¹
- C+16.8 ~kJ ~mol ⁻¹
- D+244.8 ~kJ ~mol ⁻¹
Correct answer
C. +16.8 ~kJ ~mol ⁻¹
Step-by-step solution
aligned & 1 2 I ₂( ~s )+ 1 2 Cl ₂ ICl ( g ) & H = [ 1 2 H _ b ₂(s) k₂(g) + 1 2 _ 1-1 + 1 2 _ cl - cl ]- [ _ 1-a ] & = ( 1 2 62.76+ 1 2 151.0+ 1 2 242.3 )-(211.3) & =228.03-211.3 & H =16.73 & aligned