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JEE Main 202329 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
29 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Complex Number

JEE Main 2023 · 29 January · Morning Shift · Mathematics · Complex Number

For two non-zero complex number z _ 1 and z _ 2 , if Re ( z _ 1 z _...

For two non-zero complex number z1{z}_{1} and z2{z}_{2}, if Re(z1z2)=0Re \left({z}_{1}{z}_{2}\right) = 0 and Re(z1+z2)=0Re \left({z}_{1} + {z}_{2}\right) = 0, then which of the following are possible?

(A) Im(z1)>0Im \left({z}_{1}\right) > 0 and Im(z2)>0Im \left({z}_{2}\right) > 0
(B) Im(z1)<0Im \left({z}_{1}\right) < 0 and Im(z2)>0Im \left({z}_{2}\right) > 0
(C) Im(z1)>0Im \left({z}_{1}\right) > 0 and Im(z2)<0Im \left({z}_{2}\right) < 0
(D) Im(z1)<0Im \left({z}_{1}\right) < 0 and Im(z2)<0Im \left({z}_{2}\right) < 0

Choose the correct answer from the options given below:

Options

  1. ABB and DD
  2. BBB and CC
  3. CAA and BB
  4. DAA and CC

Correct answer

B. BB and CC

Step-by-step solution

Let,

z1=x1+iy1andz2=x2+iy2{z}_{1} = {x}_{1} + i{y}_{1} and {z}_{2} = {x}_{2} + i{y}_{2}

∵Re(z1z2)=0∵ Re \left({z}_{1}{z}_{2}\right) = 0

x1x2−y1y2=0......(i){x}_{1}{x}_{2} - {y}_{1}{y}_{2} = 0 . . . . . . \left(i\right)

∵Re(z1+z2)=0∵ Re \left({z}_{1} + {z}_{2}\right) = 0

x1+x2=0......(ii){x}_{1} + {x}_{2} = 0 . . . . . . \left(ii\right)

From equations \left(i\right)and(ii)and \left(ii\right) we get

x12+y1y2=0{{x}_{1}}^{2} + {y}_{1}{y}_{2} = 0

⇒y1y2=−x12⇒ {y}_{1}{y}_{2} = - {{x}_{1}}^{2}

Therefore Im(z1)andIm(z2)Im ( {z}_{1} ) and Im ( {z}_{2} ) are of opposite sign

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