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JEE Main 202127 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
27 August
Shift
Evening Shift
Subject
Mathematics
Chapter
Complex Number

JEE Main 2021 · 27 August · Evening Shift · Mathematics · Complex Number

Let z _ 1 and z _ 2 be two complex numbers such that arg( z _ 1 - z...

Let z1andz2{z}_{1} and {z}_{2} be two complex numbers such that arg(z1−z2)=π4andz1,z2satisfytheequation∣z−3∣=Re(z)arg\left({z}_{1} - {z}_{2}\right) = \dfrac{\pi}{4} and {z}_{1}, {z}_{2} satisfy the equation \left|z - 3\right| = Re ( z ). Then the imaginary part z1+z2{z}_{1} + {z}_{2} is equal to

Correct answer

0

Step-by-step solution

Let z1=x1+iy1,z2=x2+iy2{z}_{1} = {x}_{1} + i{y}_{1}, {z}_{2} = {x}_{2} + i{y}_{2}
z1−z2=(x1−x2)+i(y1−y2)<br/>{z}_{1} - {z}_{2} = \left({x}_{1} - {x}_{2}\right) + i\left({y}_{1} - {y}_{2}\right)<br />∵ arg \left({z}_{1} - {z}_{2}\right)=\dfrac{\pi}{4}⇒⇒\tan^{- 1}\left(\dfrac{{y}_{1} - {y}_{2}}{{x}_{1} - {x}_{2}}\right) = \dfrac{\pi}{4}<br/><br />⇒ {y}_{1} - {y}_{2} = {x}_{1} - {x}_{2} - - - - ( 1 )<br/>∣z1−3∣<br />\left|{z}_{1} - 3\right| = Re \left({z}_{1}\right)⇒(x1−3)⇒ {\left({x}_{1} - 3\right)}^{2} + {y}_{1}^{2} = {x}_{1}^{2}<br/>∣z2−3∣=Re(z2)⇒(x2−3)2+y22=x22<br />\left|{z}_{2} - 3\right| = Re \left({z}_{2}\right) ⇒ {\left({x}_{2} - 3\right)}^{2} + {y}_{2}^{2} = {x}_{2}^{2}
⇒(x1−3)2−(x2−3)2+(y12−y22)=x12−x22⇒ {\left({x}_{1} - 3\right)}^{2} - {\left({x}_{2} - 3\right)}^{2} + \left({y}_{1}^{2} - {y}_{2}^{2}\right) = {x}_{1}^{2} - {x}_{2}^{2}
⇒(x1−x2)(x1+x2−6)+(y1−y2)(y1+y2)=(x1+x2)(x1−x2)⇒ \left({x}_{1} - {x}_{2}\right) \left({x}_{1} + {x}_{2} - 6\right) + \left({y}_{1} - {y}_{2}\right) \left({y}_{1} + {y}_{2}\right) = \left({x}_{1} + {x}_{2}\right) \left({x}_{1} - {x}_{2}\right)
⇒x1+x2−6+y1+y2=x1+x2⇒ {x}_{1} + {x}_{2} - 6 + {y}_{1} + {y}_{2} = {x}_{1} + {x}_{2}
⇒y1+y2=6⇒ {y}_{1} + {y}_{2} = 6
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