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JEE Main 202131 AugustMorning Shift
Exam
JEE Main
Year
2021
Date
31 August
Shift
Morning Shift
Subject
Mathematics
Chapter
Complex Number

JEE Main 2021 · 31 August · Morning Shift · Mathematics · Complex Number

A point z moves in the complex plane such that arg((z - 2)/(z + 2))...

A point zz moves in the complex plane such that arg(z−2z+2)=π4,arg\left(\dfrac{z - 2}{z + 2}\right) = \dfrac{\pi}{4}, then the minimum value of ∣z−92−2i∣2| z - 9\sqrt{2} - 2i{|}^{2} is equal to

Correct answer

0

Step-by-step solution

Given that

arg(z−2z+2)=π4arg\left(\dfrac{z - 2}{z + 2}\right) = \dfrac{\pi}{4}

Let z=x+iyz = x + iy
⇒arg(x+iy−2x+iy+2)=π4⇒ arg\left(\dfrac{x + iy - 2}{x + iy + 2}\right) = \dfrac{\pi}{4}

⇒arg((x+iy−2x+iy+2)(x+2−iyx+2−iy))=π4⇒ arg\left(\left(\dfrac{x + iy - 2}{x + iy + 2}\right)\left(\dfrac{x + 2 - iy}{x + 2 - iy}\right)\right) = \dfrac{\pi}{4}

⇒arg(x2+y2−4+4iy(x+2)2+y2)=π4⇒ arg\left(\dfrac{{x}^{2} + {y}^{2} - 4 + 4iy}{( x + 2{)}^{2} + {y}^{2}}\right) = \dfrac{\pi}{4}

⇒x2+y2−4+4iy(x+2)2+y2=tan⁡(π4)⇒ \dfrac{{x}^{2} + {y}^{2} - 4 + 4iy}{( x + 2{)}^{2} + {y}^{2}} = \tan \left(\dfrac{\pi}{4}\right)

⇒x2+y2−44y=1⇒ \dfrac{{x}^{2} + {y}^{2} - 4}{4y} = 1

x2+(y−2)2=8{x}^{2} + ( y - 2{)}^{2} = 8 ……….(1)

Equation (1)( 1 ) represents circle, whose centre (0,2)( 0, 2 ), radius 222\sqrt{2}.

Minimum distance d=∣AC−r∣d = | AC - r |
Given point A(92,2)A ( 9\sqrt{2}, 2 )

=∣AC−r∣=∣(92−22)=72= | AC - r | = ∣ ( 9\sqrt{2} - 2\sqrt{2} ) = 7\sqrt{2}

⇒⇒ Square of distance =d2=(72)2=98= {d}^{2} = ( 7\sqrt{2}{)}^{2} = 98

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