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JEE Main 202125 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
25 July
Shift
Evening Shift
Subject
Mathematics
Chapter
Complex Number

JEE Main 2021 · 25 July · Evening Shift · Mathematics · Complex Number

The equation of a circle is Re ( z ^ 2 ) + 2 (Im(z)) ^ 2 + 2 Re (z)...

The equation of a circle is Re(z2)+2(Im(z))2+2Re(z)=0,Re \left({z}^{2}\right) + 2{\left(Im\left(z\right)\right)}^{2} + 2 Re \left(z\right) = 0, where z=x+iy.z = x + iy . A line which passes through the centre of the given circle and the vertex of the parabola, x2−6x−y+13=0,{x}^{2} - 6x - y + 13 = 0, has yy-intercept equal to _________.

Correct answer

0

Step-by-step solution

We have, Re(z2)+2(Im(z))2+2Re(z)=0Re \left({z}^{2}\right) + 2{\left(Im \left(z\right)\right)}^{2} + 2 Re \left(z\right) = 0

where z=x+iyz = x + iy

Equation of circle is \left({x}^{2} - {y}^{2}\right) + 2{y}^{2} + 2x = 0</p><p></p><p>{x}^{2} + {y}^{2} + 2x = 0</p><p>Centre:(−1,0)</p><p>Centre: \left(- 1, 0\right)

Parabola : (x−3)2=y−4{\left(x - 3\right)}^{2} = y - 4

Vertex : \left(3, 4\right)</p><p>Equationofline</p><p>Equation of line≡ y - 0 = \dfrac{4 - 0}{3 + 1}\left(x + 1\right)

⇒y=x+1⇒ y = x + 1

Hence, y−y - intercept = 1 .

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