Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202124 Feb 2021Morning ShiftMathematicsComplex NumberActual

If the least and the largest real values of α , for which the equation z + α z - 1 + 2 i = 0 z ∈ C and i = - 1 has a solution, are p and q respectively; then 4 p 2 + q 2 is equal to_______.

Correct answer

0

Step-by-step solution

Put z = x + i y x + i y + α x + i y - 1 + 2 i = 0 ⇒    x + α x - 1 2 + y 2 + i y + 2 = 0 + 0 i ⇒   y + 2 = 0 and x + α x - 1 2 + y 2 = 0 ⇒   y = - 2 and α 2 = x 2 x 2 - 2 x + 5 Now x 2 x 2 - 2 x + 5 ∈ 0 , 5 4 ∴   α 2 ∈ 0 , 5 4 ⇒ α ∈ - 5 2 , 5 2 ∴   p = - 5 2 ; q = 5 2 ⇒   4 p 2 + q 2 = 4 5 4 + 5 4 = 10

Practice Complex Number on Quantrex Academy →

More from Complex Number

The number of values of z C , satisfying the equations |z-(4+8i)|= 10 and |z-(3+5i)|+|z-(5+11i)|=4 5 , is: 2026Let S = z C : z^2 + 6 ,iz - 3 = 0 . Then _ z S z^8 is equal to : 2026Let the set of all values of k R such that the equation z( z + 2 + i) + k(2 + 3i) = 0 , z C , has at least one solution, be the interval [ , ] . Then 9( + ) is equal to: 2026Let z₁, z₂ C be the distinct solutions of the equation z^2 + 4z - (1 + 12i) = 0 . Then |z₁|^2 + |z₂|^2 is equal to : 2026Let S= z C : z^2+4z+16=0 . Then _ z S |z+ 3 i|^2 is equal to: 2026Let z be a complex number such that |z+2| = |z-2| and ( z+3 z-i ) = 4 . Then |z|^2 is equal to: 2026Let the circles C₁ : |z| = r and C₂ : |z - 3 - 4i| = 5 , z C , be such that C₂ lies within C₁ . If z₁ moves on C₁ , z₂ moves on C₂ and |z₁ - z₂| = 2 , then |z₁ - z₂| is equal to: 2026Let x and y be real numbers such that 50 ( 2x 1+3i - y 1-2i ) = 31 + 17i , i = -1 . Then the value of 10(x - 3y) is : 2026 Full Complex Number list All JEE Main PYQs