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JEE Main 20188 April
Exam
JEE Main
Year
2018
Date
8 April
Subject
Mathematics
Chapter
Complex Number

JEE Main 2018 · 8 April · Mathematics · Complex Number

If α, β ∈ C are the distinct roots of the equation x ^ 2 - x + 1 =...

If α,β∈C\alpha, \beta \in C are the distinct roots of the equation x2−x+1=0,{x}^{2} - x + 1 = 0, then α101+β107{\alpha}^{101} + {\beta}^{107} is equal to

Options

  1. A22
  2. B−1- 1
  3. C00
  4. D11

Correct answer

D. 11

Step-by-step solution

x2−x+1=0{x}^{2} - x + 1 = 0

Roots are −ω,−ω2- \omega, - {\omega}^{2}.

α101+β107=(−ω)101+(−ω2)107{\alpha}^{101} + {\beta}^{107} = {\left(- \omega\right)}^{101} + {\left(- {\omega}^{2}\right)}^{107}

=−ω2−ω(∵ω3=1)= - {\omega}^{2} - \omega\left(∵ {\omega}^{3} = 1\right)

=−(ω2+ω)= - \left({\omega}^{2} + \omega\right)

=1(∵1+ω+ω2=0)= 1\left(∵ 1 + \omega + {\omega}^{2} = 0\right)

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