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JEE Main 20179 AprilOnline
Exam
JEE Main
Year
2017
Date
9 April
Mode
Online
Subject
Mathematics
Chapter
Complex Number

JEE Main 2017 · 9 April · Online · Mathematics · Complex Number

The equation Im((iz - 2)/(z - i)) + 1 = 0, z ∈ C, z ≠ i represents...

The equation Im(iz−2z−i)+1=0,z∈C,z≠iIm\left(\dfrac{iz - 2}{z - i}\right) + 1 = 0, z \in C, z \ne i represents a part of a circle having radius equal to :

Options

  1. A11
  2. B22
  3. C34\dfrac{3}{4}
  4. D12\dfrac{1}{2}

Correct answer

C. 34\dfrac{3}{4}

Step-by-step solution

Let z=x+iy,z = x + iy, then

Im[(ix−y−2x+(y−1)i)(x−(y−1)ix−(y−1)i)]+1=(y−1)(y+2)+x2x2+(y−1)2+1=0Im\left[\left(\dfrac{ix - y - 2}{x + \left(y - 1\right)i}\right)\left(\dfrac{x - \left(y - 1\right)i}{x - \left(y - 1\right)i}\right)\right] + 1 = \dfrac{\left(y - 1\right)\left(y + 2\right) + {x}^{2}}{{x}^{2} + {\left(y - 1\right)}^{2}} + 1 = 0

⇒2x2+2y2−y−1=0⇒ 2{x}^{2} + 2{y}^{2} - y - 1 = 0

⇒x2+y2−y2−12=0⇒ {x}^{2} + {y}^{2} - \dfrac{y}{2} - \dfrac{1}{2} = 0

Center (0,14)( 0, \dfrac{1}{4} )

Radius =g2+f2−c= \sqrt{{g}^{2} + {f}^{2} - c}

Radius=116+12=916=34= \sqrt{\dfrac{1}{16} + \dfrac{1}{2}} = \sqrt{\dfrac{9}{16}} = \dfrac{3}{4}

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