JEE Main 202226 JulyEvening Shift
- Exam
- JEE Main
- Year
- 2022
- Date
- 26 July
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Definite Integration
JEE Main 2022 · 26 July · Evening Shift · Mathematics · Definite Integration
∫ _ 0 ^ 20π (| x| + | x|) ^ 2 dx is equal to:
is equal to:
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
Let
We know that the period of \left|\sin x\right| + \left|\cos x\right|\dfrac{\pi}{2}I = 40{∫}_{0}^{\dfrac{\pi}{2}}{\left(\sin x + \cos x\right)}^{2}dxI = 40{∫}_{0}^{\dfrac{\pi}{2}}\left(1 + \sin 2x\right)dx= 40{\left(x - \dfrac{\cos 2x}{2}\right)}_{0}^{\dfrac{\pi}{2}} = 40\left(\dfrac{\pi}{2} - \dfrac{cos \pi}{2} + \dfrac{\cos 0}{2}\right)I = 20 \left[\pi + 2\right]