Let a, b, c be such that b(a+c) ≠ 0 . If | array ccc a & a+1 & a-1...
Let a,b,c be such that b(a+c)=0. If \left|a−bca+1b+1c−1a−1b−1c+1\right|+\left|a+1a−1(−1)n+2ab+1b−1(−1)n+1bc−1c+1(−1)nc\right|=0,thenthevalueof′n$ ' is
Options
Azero
Bany even integer
Cany odd integer
Dany integer
Correct answer
C. any odd integer
Step-by-step solution
a−bca+1b+1c−1a−1b−1c+1+(−1)na+1a−1ab+1b−1−bc−1c+1c=a−bca+1b+1c−1a−1b−1c+1+(−1)na+1b+1c−1a−1b−1c+1a−bc=a−bca+1b+1c−1a−1b−1c+1+(−1)n+1a+1b+1c−1a−bca−1b−1c+1=a−bca+1b+1c−1a−1b−1c+1+(−1)n+2a−bca+1b+1c−1a−1b−1c+1This is equal to zero only if n+2 is odd i.e. n is odd integer.
