Let a, b, c be such that b(a+c) 0 . If | array ccc a & a+1 & a-1 -b & b+1 & b-1 c & c-1 & c+1 array |+ | array ccc a+1 & b+1 & c-1 a-1 & b-1 & c+1 (-1)^ n+2 a & (-1)^ n+1 b & (-1)^n c array |=0 , then the value of ' n ' is

Step-by-step solution

aligned & | array ccc a & a+1 & a-1 -b & b+1 & b-1 c & c-1 & c+1 array |+(-1)^n | array ccc a+1 & b+1 & c-1 a-1 & b-1 & c+1 a & -b & c array |= | array ccc a & a+1 & a-1 -b & b+1 & b-1 c & c-1 & c+1 array |+(-1)^n | array cccc a+1 & a-1 & a b+1 & b-1 & -b c-1 & c+1 & c array | & = | array ccc a & a+1 & a-1 -b & b+1 & b-1 c & c-1 & c+1 array |+(-1)^ n+1 | array ccc a+1 & a & a-1 b+1 & -b & b-1 c-1 & c & c+1 array |= | array ccc a & a+1 & a-1 -b & b+1 & b-1 c & c-1 & c+1 array |+(-1)^ n+2 | array ccc a & a+1 & a-1 -b