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JEE Main 2009
Exam
JEE Main
Year
2009
Subject
Mathematics
Chapter
Determinants

JEE Main 2009 · Mathematics · Determinants

Let A and B denote the statements A: α+ β+ γ=0 B: α+ β+ γ=0 If...

Let AA and BB denote the statements A: cos⁡α+cos⁡β+cos⁡γ=0\cos \alpha+\cos \beta+\cos \gamma=0 B: sin⁡α+sin⁡β+sin⁡γ=0\sin \alpha+\sin \beta+\sin \gamma=0 If cos⁡(β−γ)+cos⁡(γ−α)+cos⁡(α−β)=−32\cos (\beta-\gamma)+\cos (\gamma-\alpha)+\cos (\alpha-\beta)=-\frac{3}{2}, then

Options

  1. AAA is true and BB is false
  2. BAA is false and BB is true
  3. Cboth AA and BB are true
  4. Dboth AA and BB are false

Correct answer

C. both AA and BB are true

Step-by-step solution

cos⁡(β−γ)+cos⁡(γ−α)+cos⁡(α−β)=−32⇒2[cos⁡(β−γ)+cos⁡(γ−α)+cos⁡(α−β)]+3=0⇒2[cos⁡(β−γ)+cos⁡(γ−α)+cos⁡(α−β)]+sin⁡2α+cos⁡2α+sin⁡2β+cos⁡2β+sin⁡2γ+cos⁡2γ=0⇒(sin⁡α+sin⁡β+sin⁡γ)2+(cos⁡α+cos⁡β+cos⁡γ)2=0\begin{aligned}& \cos (\beta-\gamma)+\cos (\gamma-\alpha)+\cos (\alpha-\beta)=-\frac{3}{2}\\ & \Rightarrow 2[\cos (\beta-\gamma)+\cos (\gamma-\alpha)+\cos (\alpha-\beta)]+3=0 \\ & \Rightarrow 2[\cos (\beta-\gamma)+\cos (\gamma-\alpha)+\cos (\alpha-\beta)]+\sin ^2 \alpha+\cos ^2 \alpha+\sin ^2 \beta+\cos ^2 \beta+\sin ^2 \gamma+\cos ^2 \gamma=0 \\ & \Rightarrow(\sin \alpha+\sin \beta+\sin \gamma)^2+(\cos \alpha+\cos \beta+\cos \gamma)^2=0 \end{aligned}
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