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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Mathematics
Chapter
Hyperbola

JEE Main 2021 · 26 August · Evening Shift · Mathematics · Hyperbola

The locus of the mid points of the chords of the hyperbola x ^ 2 -...

The locus of the mid points of the chords of the hyperbola x2−y2=4,{x}^{2} - {y}^{2} = 4, which touch the parabola y2=8x,{y}^{2} = 8x, is :

Options

  1. Ay2(x−2)=x3{y}^{2}\left(x - 2\right) = {x}^{3}
  2. Bx3(x−2)=y2{x}^{3}\left(x - 2\right) = {y}^{2}
  3. Cx2(x−2)=y3{x}^{2}\left(x - 2\right) = {y}^{3}
  4. Dy3(x−2)=x2{y}^{3}\left(x - 2\right) = {x}^{2}

Correct answer

A. y2(x−2)=x3{y}^{2}\left(x - 2\right) = {x}^{3}

Step-by-step solution

Equation of chord of hyperbola x2−y2=4{x}^{2} - {y}^{2} = 4 with mid-point (h,k)\left(h, k\right) is given by xh−yk=h2−k2xh - yk = {h}^{2} - {k}^{2}

⇒yk=xh−h2+k2⇒ yk = xh - {h}^{2} + {k}^{2}

⇒y=hxk+(k2−h2k)⇒ y = \dfrac{hx}{k} + \left(\dfrac{{k}^{2} - {h}^{2}}{k}\right)

This will touch the parabola y2=8x,{y}^{2} = 8x, if

⇒k2−h2k=2h/k⇒ \dfrac{{k}^{2} - {h}^{2}}{k} = \dfrac{2}{h / k}

⇒2kh=k2−h2k⇒ \dfrac{2k}{h} = \dfrac{{k}^{2} - {h}^{2}}{k}

⇒h3+2k2−k2h=0⇒ {h}^{3} + 2{k}^{2} - {k}^{2}h = 0
∴∴ Equation of locus is x3+2y2−y2x=0{x}^{3} + 2{y}^{2} - {y}^{2}x = 0

⇒x3=y2(x−2)⇒ {x}^{3} = {y}^{2}\left(x - 2\right)

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