JEE Main202229 Jul 2022Evening ShiftMathematicsIndefinite IntegrationActual
For I x = ∫ sec 2 x - 2022 sin 2022 x d x , if I π 4 = 2 1011 , then
Options
- A3 1010 I π 3 - I π 6 = 0
- B3 1010 I π 6 - I π 3 = 0
- C3 1011 I π 3 - I π 6 = 0
- D3 1011 I π 6 - I π 3 = 0
Correct answer
A. 3 1010 I π 3 - I π 6 = 0
Step-by-step solution
Given, I x = ∫ sec 2 x - 2022 sin 2022 x d x On rearranging we get, ⇒ I x = ∫ sec 2 x ⏟ I I · sin - 2022 x ⏟ I d x - 2022 ∫ sin - 2022 x d x Now using integration by parts we get, ⇒ I x = tan x . sin x - 2022 + ∫ 2022 tan x · sin x - 2023 cos x d x - 2022 ∫ sin x - 2022 d x ⇒ I x = tan x . sin x - 2022 + ∫ 2022 tan x · sin x - 2022 cos x sin x d x - 2022 ∫ sin x - 2022 d x ⇒ I x = tan x . sin x - 2022 + ∫ 2022 sin x -