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JEE Main2005MathematicsProperties of TrianglesActual

In a triangle PQR , R = 2 . If ( P 2 ) and ( Q 2 ) are the roots of a x^2+b x+c=0, a 0 then

Options

  1. Aa=b+c
  2. Bc=a+b
  3. Cb=c
  4. Db=a+c

Correct answer

B. c=a+b

Step-by-step solution

( P 2 ), ( Q 2 ) are the roots of ax ^2+ bx + c =0 ( P 2 )+ ( Q 2 )=- b a ( P 2 ) ( Q 2 )= c a ( P 2 )+ ( Q 2 ) 1- ( P 2 ) ( Q 2 ) = ( P 2 + Q 2 )=1 - b a 1- c a =1 - b a = a a - c a - b = a - c c = a + b .

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