Let and respectively be the maximum and the minimum values of the function f( )=4 ( ⁴ ( 7 2 - )+ ⁴(11 + ) )-2 ( ⁶ ( 3 2 - )+ ⁶(9 - ) ), R . Then +2 is equal to :

Step-by-step solution

f( ) = 4 ^4 ( 7 2 - ) + ^4(11 + ) - 2 ^2 ( 3 2 - ) + ^2(9 - ) f( ) = 4( ^4( ) + ^4( )) - 2( ^6 + ^6 ) f( ) = 4(1 - 2 ^2 ^2 ) - 2(1 - 3 ^2 ^2 ) f( ) = 2 - 2 ^2 ^2 f( ) = 2 - ^2(2 ) 2 = f( )_ max = 2 = f( )_ min = 3 2 + 2 = 5