JEE Main202622 January 2026Evening ShiftMathematicsTrigonometric Ratios & IdentitiesActual
Let ( + )=- 1 10 and ( - )= 3 8 , where 0< < 3 and 0< < 4 . If 2 = 3(1-r 5 ) 11 (s+ 5 ) , r, s N , then r+s is equal to _ _ _ _ .
Correct answer
0
Step-by-step solution
2 = [( + )+( - )] 2 = ( + )+ ( - ) 1- ( + ) ( - ) 2 = (- 99 + 3 55 ) 1-( 99 ) ( 3 55 ) 2 = -3 11 + 3 5 11 1+ 9 11 5 11 2 = 3(1-11 5 ) 11 (9+ 5 ) r =11, ~s =9 r + s =20