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JEE Main 20257 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Evening Shift
Subject
Physics
Chapter
Capacitance

JEE Main 2025 · 7 April · Evening Shift · Physics · Capacitance

A parallel plate capacitor has charge 5 × 10^ -6 C . A dielectric...

A parallel plate capacitor has charge 5×10−6C5 \times 10^{-6} \mathrm{C}. A dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is 4×10−6C4 \times 10^{-6} \mathrm{C} then the dielectric constant of the slab is ________.

Correct answer

0

Step-by-step solution

Qin=Q(1−1 K)4×10−6=5×10−6(1−1 K)1−1 K=45 K=5\begin{aligned} & \mathrm{Q}_{\mathrm{in}}=\mathrm{Q}\left(1-\frac{1}{\mathrm{~K}}\right) \\ & 4 \times 10^{-6}=5 \times 10^{-6}\left(1-\frac{1}{\mathrm{~K}}\right) \\ & 1-\frac{1}{\mathrm{~K}}=\frac{4}{5} \\ & \mathrm{~K}=5\end{aligned}
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