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JEE Main 20254 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Evening Shift
Subject
Physics
Chapter
Capacitance

JEE Main 2025 · 4 April · Evening Shift · Physics · Capacitance

Three parallel plate capacitors C_1, C_2 and C_3 each of...

Three parallel plate capacitors C1,C2\mathrm{C}_1, \mathrm{C}_2 and C3\mathrm{C}_3 each of capacitance 5μ F5 \mu \mathrm{~F} are connected as shown in figure. The effective capacitance between points A and B, when the space between the parallel plates of C1C_1 capacitor is filled with a dielectric medium having dielectric constant of 4, is :
Three parallel plate capacitors C_1, C_2 and C_3 each of capacitance 5 μ ~F are connected as shown in figure. The

Options

  1. A22.5μ F22.5 \mu \mathrm{~F}
  2. B7.5μ F7.5 \mu \mathrm{~F}
  3. C9μ F9 \mu \mathrm{~F}
  4. D30μ F30 \mu \mathrm{~F}

Correct answer

C. 9μ F9 \mu \mathrm{~F}

Step-by-step solution

After dielectric
<br/>C1=4CC1=4×5=20μ FC2=C3=5μ F<br/>\begin{aligned}<br/>& \mathrm{C}_1=4 \mathrm{C} \\ & \mathrm{C}_1=4 \times 5=20 \mu \mathrm{~F} \\ & \mathrm{C}_2=\mathrm{C}_3=5 \mu \mathrm{~F}<br/>\end{aligned}
C1&C2\mathrm{C}_1 \& \mathrm{C}_2 are in series which is parallel to C3\mathrm{C}_3 So
<br/>Ccq=C1C2C1+C2+C3⇒20×520+5+5=4+5=9μ F<br/>\begin{aligned}<br/>& C_{c q}=\frac{C_1 C_2}{C_1+C_2}+C_3 \Rightarrow \frac{20 \times 5}{20+5}+5 \\ & =4+5=9 \mu \mathrm{~F}<br/>\end{aligned}
Correct Option (3)
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