In an electrical circuit drawn below the amount of charge stored in the capacitor is _______ μC .

Step-by-step solution

In steady state there will be no current in branch of capacitor, so no voltage drop across R 2 = 5 Ω I 2 = 0 I 1 = I 3 = 10 4 + 6 = 1 A V R 3 = V c + V R 2 V R 2 = 0 ⇒ I 3 R 3 = V c ⇒ V c = 1 × 6 = 6 volt Therefore, charge on capacitor q c = C V c = 10 × 6 = 60 μC