In the given figure the total charge stored in the combination of capacitors is 100 µ C . The value of ‘ x ’ is ______________.

Step-by-step solution

All the capacitors are in parallel combination and therefore potential drop across each capacitor would be the same. Charge on the capacitor can be written as, Q = C V . The charge on C 1 is Q 1 = 2 × 10 = 20   μC The charge on C 2 is Q 2 = x × 10 = 10 x   μC The charge on C 3 is Q 3 = 3 × 10 = 30   μC By the given data. C 1 + C 2 + C 3 = 100   μC ⇒ 10 2 + x + 3 = 100 ⇒ x = 5