In the network shown below, the charge accumulated in the capacitor in steady state will be:

Step-by-step solution

In steady state, capacitor behaves as open circuit, so no current will flow. The total resistance of the circuit is, R = 6 + 4   Ω = 10   Ω The current flowing through the circuit is I = 3   V 10   Ω Potential difference on 6   Ω resistor V ' = 3 10 × 6 = 1 . 8   V The charge on the capacitor is, Q = C V ' = 4   μF × 1 . 8   V = 7 . 2   μC