If the charge on a capacitor is increased by 2 C , the energy stored in it increases by 44 % . The original charge on the capacitor is (in C )

Step-by-step solution

Energy stored in a capacitor is given by E = Q 2 2 C . Let initial charge be Q 0 . Then, 1 . 44 Q 0 2 2 C = Q 0 + 2 2 2 C ⇒ 1 . 2 Q 0 = Q 0 + 2 Q 0 = 2 0 . 2 = 10   C