- Exam
- JEE Main
- Year
- 2022
- Date
- 24 June
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Capacitance
JEE Main 2022 · 24 June · Morning Shift · Physics · Capacitance
A parallel plate capacitor is formed by two plates each of area 30π...
A parallel plate capacitor is formed by two plates each of area separated by . A material of dielectric strength is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is , the value of dielectric constant of the material is :
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Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
The dielectric strength given is .and the separation is . Therefore, maximum potential difference that can be applied will be,
{V}_\max = 3 . 6 \times {10}^{7} \times d.
Now,
C = \dfrac{{q}_\max}{{V}_\max} ⇒ \dfrac{k{ε}_{0}A}{d} = \dfrac{7 \times {10}^{- 7}}{3 . 6 \times {10}^{7} \times d}k = \dfrac{d}{{ε}_{0} \times 30\pi \times {10}^{- 4}} \times \dfrac{7 \times {10}^{- 7}}{3 . 6 \times {10}^{7} \times d} = 2 . 33