JEE Main202127 Jul 2021Morning ShiftPhysicsCapacitanceActual
A capacitor of capacitance C = 1 μ F is suddenly connected to a battery of 100 V through a resistance R = 100 Ω . The time taken for the capacitor to be charged to get 50 V is: (Take ln 2 = 0 . 69 )
Options
- A1 . 44 × 10 - 4   s
- B3 . 33 × 10 - 4   s
- C0 . 69 × 10 - 4   s
- D0 . 30 × 10 - 4   s
Correct answer
C. 0 . 69 × 10 - 4   s
Step-by-step solution
V = V 0 1 - e - t R C 50 = 100 1 - e - t R C t = 0 . 69 × 10 - 4   sec .