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JEE Main 202127 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
27 July
Shift
Morning Shift
Subject
Physics
Chapter
Capacitance

JEE Main 2021 · 27 July · Morning Shift · Physics · Capacitance

In the reported figure, a capacitor is formed by placing a compound...

In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be: (Given the area of the plate =A= A )

In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate

Options

  1. A1534Kε0Ad\dfrac{15}{34}\dfrac{K{ε}_{0}A}{d}
  2. B156Kε0Ad\dfrac{15}{6}\dfrac{K{ε}_{0}A}{d}
  3. C256Kε0Ad\dfrac{25}{6}\dfrac{K{ε}_{0}A}{d}
  4. D96Kε0Ad\dfrac{9}{6}\dfrac{K{ε}_{0}A}{d}

Correct answer

A. 1534Kε0Ad\dfrac{15}{34}\dfrac{K{ε}_{0}A}{d}

Step-by-step solution

1Ceff=dK∈0A+2d3K∈0A+3d5∈0A\dfrac{1}{{C}_{eff}} = \dfrac{d}{K{\in}_{0}A} + \dfrac{2d}{3K{\in}_{0}A} + \dfrac{3d}{5{\in}_{0}A}

Ceff=15K∈0A34d{C}_{eff} = \dfrac{15K{\in}_{0}A}{34d}

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