JEE Main202116 Mar 2021Morning ShiftPhysicsCapacitanceActual
For changing the capacitance of a given paralle plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3 4 d , where d is the separation between the plates of parallel plate capacitor. The new capacitance C ' in terms of original capacitance C 0 is given by the following relation :
Options
- AC ' = 3 + K 4 K C 0
- BC ' = 4 + K 3 C 0
- CC ' = 4 K   K + 3 C 0
- DC ' = 4 3 + K C 0
Correct answer
C. C ' = 4 K   K + 3 C 0
Step-by-step solution
C 0 = ϵ 0 A   d C ' = C 1 and C 2 in series. i.e. 1 C ' = 1 C 1 + 1 C 2 1 C ' = 3 d / 4 ϵ 0 K A + d / 4 ϵ 0   A 1 C ' = d 4 ϵ 0 A 3 + K K C ' = 4 K C 0 3 + K