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JEE Main20206 Sep 2020Morning ShiftPhysicsCapacitanceActual

Suppose that intensity of a laser is 315 π W m - 2 . The rms electric field, in units of V m - 1 associated with this source is close to the nearest integer is - ε 0 = 8 . 86 × 10 - 12 C 2 N m - 2 ; c = 3 × 10 8 m s - 1

Correct answer

0

Step-by-step solution

1 2 C ∈ 0 E m s 2 = 315 π E rms = 315 × 2 π × 3 × 10 8 × 8 . 86 × 10 - 12 = 630 83 . 4612 × 10 - 4 = 7 . 5484 × 10 4 = 2 . 75 × 10 2 = 2 . 75 × 10 2 = 275

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