In the circuit shown, charge on the 5 capacitor is :

In the circuit shown, charge on the $5\muF$ capacitor is :

Options

A $18 . 00\muC$
B $10 . 90\muC$
C $16 . 36\muC$
D $5 . 45\muC$

Correct answer

D. $5 . 45\muC$

Step-by-step solution

${V}_{B} = 6{V}_{C} = x{V}_{D} = 6$

In the circuit shown, charge on the 5 capacitor is :

$- 91 + 92 + 93 = 0$
$- 2 ( 6 - x ) + 4 ( x - 6 ) + 5 ( x - 0 ) = 0$
$- 12 + 2x + 4x - 24 + 5x = 0$
$11x = 36 ⇒ x = \dfrac{36}{11}; {q}_{3} = 5 \times \dfrac{36}{11} = \dfrac{180}{11}\muC$

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