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JEE Main20205 Sep 2020Evening ShiftPhysicsCapacitanceActual

In the circuit shown, charge on the 5 μ F capacitor is :

Options

  1. A18 . 00 μ C
  2. B10 . 90 μ C
  3. C16 . 36 μ C
  4. D5 . 45 μ C

Correct answer

D. 5 . 45 μ C

Step-by-step solution

V B = 6    V C = x    V D = 6 - 91 + 92 + 93 = 0 - 2 ( 6 - x ) + 4 ( x - 6 ) + 5 ( x - 0 ) = 0 - 12 + 2   x + 4   x - 24 + 5   x = 0 11 x = 36 ⇒ x = 36 11 ; q 3 = 5 × 36 11 = 180 11 μ C

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