JEE Main201912 Apr 2019Evening ShiftPhysicsCapacitanceActual
In the given circuit, the charge on 4   μ F capacitor will be:
Options
- A9.6 μ C
- B5.4 μ C
- C24 μ C
- D13.4 μ C
Correct answer
C. 24 μ C
Step-by-step solution
The given circuit can be redrawn as: Charge on 4   μ F capacitor: Q = 4 × 6 4 + 6 × 10 Q = 24   μC in series combination charge remains same. so, Q 4 μ F = Q 6 μ F = 24   μ C