JEE Main201910 Apr 2019Morning ShiftPhysicsCapacitanceActual
Figure shows charge ( q ) versus voltage ( V ) graph for series and parallel combination of two given capacitors. The capacitances are:
Options
- A60 μ F and 40 μ F
- B50 μ F and 30 μ F
- C20 μ F and 30 μ F
- D40 μ F and 10 μ F
Correct answer
D. 40 μ F and 10 μ F
Step-by-step solution
Q = C V The slope of graph will give the equivalent capacitance of the combination. From graph A : C 1 + C 2 = 500 10 = 50 …(i) From graph B : C 1 C 2 C 1 + C 2 = 80 10 = 8 …(ii) From equation (i) & (ii) C 1 C 2 = 400 …(iii) C 1 + 400 C 1 = 50 ⇒ C 1 2 - 50 C 1 + 400 = 0 C 1 = 50 ± 2500 - 1600 2 = 50 ± 30 2 = 10 μ F , 40 μ F