JEE Main20199 Apr 2019Evening ShiftPhysicsCapacitanceActual
The parallel combination of two air filled parallel plate capacitors of capacitance C and n C is connected to a battery of voltage, V . When the capacitors are fully charged, the battery is removed and after that a dielectric material of dielectric constant K is placed the two plates of the first capacitor. The new potential difference of the combined system is:
Options
- An + 1 V K + n
- Bn V K + n
- CV K + n
- DV
Correct answer
A. n + 1 V K + n
Step-by-step solution
i) ii) Battery disconnected after full charge, Total charge of the system, = C V + n C V = n + 1 C V iii) Inserting dielectric of constant K Common potential, V C = t o t a l   c h a r g e t o t a l   c a p a c i t a n c e = n + 1 C V K C + n C = n + 1 V K + n