The equivalent capacitance between A and B in the circuit given below is:

Step-by-step solution

The simplified circuit of the circuit given in question as follows: The equivalent capacitance between C & D capacitors of 2 F , 5 F and 5 F are in parallel. C _ CD =2+5+5=12 F ( In parallel grouping C _ eq = C ₁+ C ₂+ .+ C _ n ) Similarly equivalent capacitance between E & BC _ EB =4+2=6 F Now equivalent capacitance between A & B 1 C _ eq = 1 6 + 1 12 + 1 6 = 5 12 C _ eq = 12 5 =2.4 F ( In series grouping, 1 C _ eq = 1 C ₁ + 1 C ₂ + + 1 C _ n )