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JEE Main 201815 April
Exam
JEE Main
Year
2018
Date
15 April
Subject
Physics
Chapter
Capacitance

JEE Main 2018 · 15 April · Physics · Capacitance

The equivalent capacitance between A and B in the circuit is given...

The equivalent capacitance between AA and BB in the circuit is given below.
The equivalent capacitance between A and B in the circuit is given below.

Options

  1. A3.6μF3 . 6\mu F
  2. B2.4μF2 . 4\mu F
  3. C4.94 . 9 \muF\muF
  4. D5.45 . 4 \muF\muF

Correct answer

B. 2.4μF2 . 4\mu F

Step-by-step solution

Simplified circuit, The equivalent capacitance between A and B in the circuit is given below.

The equivalent capacitance between A and B in the circuit is given below.

⇒1Ceq=16+112+16=512⇒Ceq=125=2.4\muF⇒ \dfrac{1}{{C}_{eq}} = \dfrac{1}{6} + \dfrac{1}{12} + \dfrac{1}{6} = \dfrac{5}{12} ⇒ {C}_{eq} = \dfrac{12}{5} = 2.4\muF

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