In the given circuit diagram, when the current reaches a steady-state in the circuit, the charge on the capacitor of capacitance C will be:

Step-by-step solution

In steady state, current through capacitor will be zero, so current through r 1 will be zero. Hence, the net current flowing in the circuit will be, I = E r + r 2 The potential difference across the capacitor will be, V 2 = I × r 2 = E r 2 r + r 2 Therefore, charge on the capacitor plate will be, q = C V 2 = C E r 2 r + r 2