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JEE Main 201323 AprilOnline
Exam
JEE Main
Year
2013
Date
23 April
Mode
Online
Subject
Physics
Chapter
Capacitance

JEE Main 2013 · 23 April · Online · Physics · Capacitance

A parallel plate capacitor of area 60 ~cm^2 and separation 3 ~mm is...

A parallel plate capacitor of area 60 cm260 \mathrm{~cm}^2 and separation 3 mm3 \mathrm{~mm} is charged initially to 90μC90 \mu \mathrm{C}. If the medium between the plate gets slightly conducting and the plate loses the charge initially at the rate of 2.5×10−8C/s2.5 \times 10^{-8} \mathrm{C} / \mathrm{s}, then what is the magnetic field between the plates ?

Options

  1. A2.5×10−8 T2.5 \times 10^{-8} \mathrm{~T}
  2. B2.0×10−7 T2.0 \times 10^{-7} \mathrm{~T}
  3. C1.63×10−11 T1.63 \times 10^{-11} \mathrm{~T}
  4. DZero

Correct answer

D. Zero

Step-by-step solution

Magnetic field between the plates in this case is zero.
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