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JEE Main 201322 AprilOnline
Exam
JEE Main
Year
2013
Date
22 April
Mode
Online
Subject
Physics
Chapter
Capacitance

JEE Main 2013 · 22 April · Online · Physics · Capacitance

To establish an instantaneous current of 2 ~A through a 1 μ F...

To establish an instantaneous current of 2 A2 \mathrm{~A} through a 1μF1 \mu \mathrm{F} capacitor ; the potential difference across the capacitor plates should be changed at the rate of:

Options

  1. A2×104 V/s2 \times 10^4 \mathrm{~V} / \mathrm{s}
  2. B4×106 V/s4 \times 10^6 \mathrm{~V} / \mathrm{s}
  3. C2×106 V/s2 \times 10^6 \mathrm{~V} / \mathrm{s}
  4. D4×104 V/s4 \times 10^4 \mathrm{~V} / \mathrm{s}

Correct answer

C. 2×106 V/s2 \times 10^6 \mathrm{~V} / \mathrm{s}

Step-by-step solution

As, C =QV=ItV=\frac{\mathrm{Q}}{\mathrm{V}}=\frac{\mathrm{It}}{\mathrm{V}} ⇒Vt=IC=21×10−6=2×106 V/s\begin{aligned}& \Rightarrow \frac{\mathrm{V}}{\mathrm{t}}=\frac{\mathrm{I}}{\mathrm{C}}=\frac{2}{1 \times 10^{-6}}\\ & =2 \times10^6 \mathrm{~V}/ \mathrm{s} \end{aligned}
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