Two capacitors C _ 1 and C _ 2 are charged to 120 V and 200 V...

Two capacitors

{C}_{1}

and

{C}_{2}

are charged to

\text{120 V}

and

\text{200 V}

respectively. It is found that by connecting them together the potential on each one can be made zero. Then: Two capacitors C _ 1 and C _ 2 are charged to 120 V and 200 V respectively. It is found that by connecting them

Two capacitors C _ 1 and C _ 2 are charged to 120 V and 200 V respectively. It is found that by connecting them

Options

A $3{C}_{1} + 5{C}_{2} = 0$
B $9{C}_{1} = 4{C}_{2}$
C $5{C}_{1} = 3{C}_{2}$
D $3{C}_{1} = 5{C}_{2}$

Correct answer

D. $3{C}_{1} = 5{C}_{2}$

Step-by-step solution

Two capacitors C _ 1 and C _ 2 are charged to 120 V and 200 V respectively. It is found that by connecting them

Two capacitors C _ 1 and C _ 2 are charged to 120 V and 200 V respectively. It is found that by connecting them
For potential to be made zero, after connection

$120{C}_{1} = 200{C}_{2}$

$⇒ 3{C}_{1} = 5{C}_{2}$

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