JEE Main2013PhysicsCapacitanceActual
In an LCR circuit as shown below both switches are open initially. Now switch S 1 is closed, S 2 kept open. ( q is charge on the capacitor and τ = RC is capacitive time constant). Which of the following statement is correct?
Options
- AAt t = 2 τ , q = CV 1 - e - 2
- BAt t = τ 2 ,  q = CV  1 - e -1
- CWork done by the battery is half of the energy dissipated in the resistor
- DAt t = τ , q = CV / 2
Correct answer
A. At t = 2 τ , q = CV 1 - e - 2
Step-by-step solution
q = CV 1 - e t / τ At t = 2 τ q = CV 1 - e - 2