Which of the following pairs does not have same bond order?

Step-by-step solution

(a) N ₂(14): 1 s^2 ^* 1 s^2 2 s^2 ^ 2 s^2 2 p_x^2= 2 p_y ^2 2 p_z^2 B.O. = 1 2 (N_b-N_a )= 1 2 (10-4)=3.0 CN ⁻(14): 1 s^2 ^* 1 s^2 2 s^2 ^* 2 s^2 2 p_x^2= 2 p_y^2 2 p_z^2 B.O. = 1 2 (10-4)=3.0 (b) O ₂⁺(15): 1 s^2 ^* 1 s^2 2 s^2 ^* 2 s^2 2 p_z^2 2 p_x^2= 2 p_y^2 ^ 2 p_x^1 B.O. = 1 2 (10-5)=2.5 NO (15): 1 s^2 ^* 1 s^2 2 s^2 ^ 2 s^2 2 p_z^2 2 p_x^2= 2 p_y^2 ^ 2 p_x^1 B.O. = 1 2 (10-5)=2.5 (c) F ₂⁻(19): 1 s^2 ^ 1 s^2 2 s^2 ^ 2 s^2 2 p_z^2 2 p_x^2= 2 p_y^2 ^ 2 p_x^2= ^* 2 p_y^2 ^* 2 p_z^1 B.O. = 1 2 (10-9)=0.5 O ₂²⁻(18)