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JEE Main 202226 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
26 June
Shift
Morning Shift
Subject
Physics
Chapter
Experimental Physics

JEE Main 2022 · 26 June · Morning Shift · Physics · Experimental Physics

In a vernier callipers, each cm on the main scale is divided into...

In a vernier callipers, each cmcm on the main scale is divided into 2020 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be _____ ×10−2mm\times {10}^{- 2}mm

Correct answer

0

Step-by-step solution

Vernier constant is defined as the difference between the value of one main scale division and one vernier scale division. It is also known as the least count of vernier calliper.

The main scale division of the given vernier calliper is MSD=1cm20=0.5mmMSD = \dfrac{1cm}{20} = 0 . 5mm.

LC=MSDn=0.5mm10=0.05mm=5×10−2mmLC = \dfrac{MSD}{n} = \dfrac{0 . 5mm}{10} = 0 . 05mm = 5 \times {10}^{- 2}mm

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