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A load of mass M k g is suspended from a steel wire of length 2 m and radius 1.0 m m in Searle's apparatus experiment. The increase in length produced in the wire is 4.0 m m . Now the load is fully immersed in a liquid of relative density 2 . The relative density of the material of load is 8 . The new value of increase in length of the steel wire is:

Options

  1. A4.0 m m
  2. BZero
  3. C5.0 m m
  4. D3.0 m m

Correct answer

D. 3.0 m m

Step-by-step solution

δ = ρ 0 v g × L A y δ ′ = ρ 0 - ρ L v g × L A y ⇒ δ ^ ′ δ = ρ 0 - ρ L ρ 0 = 8 - 2 8 δ ′ = 3 m m

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