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JEE Main 201912 JanuaryEvening Shift

Exam: JEE Main
Year: 2019
Date: 12 January
Shift: Evening Shift
Subject: Physics
Chapter: Experimental Physics

JEE Main 2019 · 12 January · Evening Shift · Physics · Experimental Physics

A load of mass Mkg is suspended from a steel wire of length 2m and...

A load of mass

Mkg

is suspended from a steel wire of length

2m

and radius

1.0mm

in Searle's apparatus experiment. The increase in length produced in the wire is

4.0mm .

Now the load is fully immersed in a liquid of relative density

2 .

The relative density of the material of load is

8 .

The new value of increase in length of the steel wire is:

Options

A $4.0mm$
BZero
C $5.0mm$
D $3.0mm$

Correct answer

D. $3.0mm$

Step-by-step solution

\delta = \dfrac{{ρ}_{0}vg \times L}{Ay}

{\delta}^{′} = \dfrac{\left({ρ}_{0} - {ρ}_{L}\right)vg \times L}{Ay} ⇒ \dfrac{\delta ^ ′}{\delta} = \dfrac{{ρ}_{0} - {ρ}_{L}}{{ρ}_{0}} = \dfrac{8 - 2}{8}

{\delta}^{′} = 3mm

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