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JEE Main 201912 JanuaryMorning Shift

Exam: JEE Main
Year: 2019
Date: 12 January
Shift: Morning Shift
Subject: Physics
Chapter: Experimental Physics

JEE Main 2019 · 12 January · Morning Shift · Physics · Experimental Physics

The least count of the main scale of a screw gauge is 1mm . The...

The least count of the main scale of a screw gauge is

1mm .

The minimum number of divisions on its circular scale required to measure

5\mu m

diameter of a wire is:

Options

A $50$
B $100$
C $500$
D $200$

Correct answer

D. $200$

Step-by-step solution

Least count of screw gauge $= 5\mu m$

$L . C = \dfrac{pitch}{no . ofdivoncirxularscale}$

$5\mu m = \dfrac{1mm}{N}$

$N = 200$

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